Hi community,
I'm trying to calculate the sum of two custom fields with a time entry like: 1w 5d 3h 2m and 13w 3d 19h 58m.
Here my code:
import com.atlassian.jira.component.ComponentAccessor;
def customField1 = ComponentAccessor.getCustomFieldManager().getCustomFieldObject("customfield_11111");
def customField2 = ComponentAccessor.getCustomFieldManager().getCustomFieldObject("customfield_22222");
def value1 = (String)issue.getCustomFieldValue(customField1);
def value2 = (String)issue.getCustomFieldValue(customField2);
return value1 + value2
But the result is: 1w 5d 3h 2m13w 3d 19h 58m
How can I get the right sum of: 15w 1d 23h?
Greetings,
Peter
Hi @Peter Kaufmann ,
Since your are using string values, you would have to create a custom function to sum on them.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi @Peter Kaufmann ,
I am not the best with regexps, but had a little fun with this case and it seems to work as expected :
private String sumTimes(String timeLogged1, String timeLogged2){
def minsCatcher = '[0-9]*(?=m)'
def hoursCatcher = '[0-9]*(?=h)'
def daysCatcher = '[0-9]*(?=d)'
def weeksCatcher = '[0-9]*(?=w)'
def nbMins1 = (timeLogged1 =~ minsCatcher).find()?(timeLogged1 =~ minsCatcher):"0"
def nbHours1 = (timeLogged1 =~ hoursCatcher).find()?(timeLogged1 =~ hoursCatcher):"0"
def nbDays1 = (timeLogged1 =~ daysCatcher).find()?(timeLogged1 =~ daysCatcher):"0"
def nbWeeks1 = (timeLogged1 =~ weeksCatcher).find()?(timeLogged1 =~ weeksCatcher):"0"
def nbMins2 = (timeLogged2 =~ minsCatcher).find()?(timeLogged2 =~ minsCatcher):"0"
def nbHours2 = (timeLogged2 =~ hoursCatcher).find()?(timeLogged2 =~ hoursCatcher):"0"
def nbDays2 = (timeLogged2 =~ daysCatcher).find()?(timeLogged2 =~ daysCatcher):"0"
def nbWeeks2 = (timeLogged2 =~ weeksCatcher).find()?(timeLogged2 =~ weeksCatcher):"0"
int nbMinsTotal = (nbMins1[0]==""?0:nbMins1[0].toInteger()) + (nbMins2[0]==""?0:nbMins2[0].toInteger())
int nbHoursTotal = (nbHours1[0]==""?0:nbHours1[0].toInteger()) + (nbHours2[0]==""?0:nbHours2[0].toInteger())
int nbDaysTotal = (nbDays1[0]==""?0:nbDays1[0].toInteger()) + (nbDays2[0]==""?0:nbDays2[0].toInteger())
int nbWeeksTotal = (nbWeeks1[0]==""?0:nbWeeks1[0].toInteger()) + (nbWeeks2[0]==""?0:nbWeeks2[0].toInteger())
int finalNbMins = nbMinsTotal%60
int nbHoursToAdd = nbMinsTotal/60
int finalNbHours = (nbHoursTotal + nbHoursToAdd)%24
int nbDaysToAdd = (nbHoursTotal + nbHoursToAdd)/24
int finalNbDays = (nbDaysTotal + nbDaysToAdd)%7
int nbWeeksToAdd = (nbDaysTotal + nbDaysToAdd)/7
int finalNbWeeks = nbWeeksTotal + nbWeeksToAdd
String finalTime = ((finalNbWeeks!=0)?finalNbWeeks+"w ":"")+((finalNbDays!=0)?finalNbDays+"d ":"")+((finalNbHours!=0)?finalNbHours+"h ":"")+((finalNbMins!=0)?finalNbMins+"m":"")
return finalTime.trim()
}
Let me know if that works for you !
Antoine
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Dear Antoine,
thanks for your help. In the meantime I got a simple code. I convert the time in seconds and than I calculated the sum. After this, I convert it back with:
return DateUtils.getDurationString(sum)
Now it is working. Nevertheless, thank you Antoine.
Best regards,
Peter
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Glad you found a solution !
Is the output formatted as well ? (e.g. 4w 5d 3h 2m)
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Nice, glad you shared, I did not know about that one. :)
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Online forums and learning are now in one easy-to-use experience.
By continuing, you accept the updated Community Terms of Use and acknowledge the Privacy Policy. Your public name, photo, and achievements may be publicly visible and available in search engines.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.