How to leave out fodlers in .yml file?

[Rasmus Hye]

Hi!

I'm using Bitbucket Pipelines to deploy files to FTP server.

I need the .yml file to zip only one folder in my repository.

Currently I managed it to leave out all files, but does anyone know how to make it leave out folders?

The two folders I need it to leave out is /src and /node_modules. But it doesn't seem to work the same way as with the files.

This is my .yml code:

image: samueldebruyn/debian-git

pipelines: 
   default: 
      - step: 
         script:  
            - apt-get update 
            - apt-get -qq install zip curl 
            - zip -r $BITBUCKET_REPO_SLUG.zip . -x *.git* *.yml *.js *.wbl *.json *src* *node_modules*
            - curl -T $BITBUCKET_REPO_SLUG.zip ftp://left-out/ --user $FTP_USERNAME:$FTP_PASSWORD

[Linette]

Hi Rasmus,

You are SO CLOSE!! In your example, if you escape the asterisks with slashes it will work for you so the command should be:

            - zip -r $BITBUCKET_REPO_SLUG.zip . -x *.git* *.yml *.js *.wbl *.json \*src* \*node_modules*

 you could also try using quotes, but this seemed the most direct method to me.