Hi,
I would like to find all the issues from a specific project, that have a linked issue.
I can't use issue in linkedIssues("") because I don't want to know if there issues linked to a specific ticket, I just want all the issues that have a linked issue.
Do I have to install https://marketplace.atlassian.com/plugins/org.craftforge.jira.craftforge-jql-functions-plugin ?
In that case, what would be the Query?
Thanks for your help :)
Delphine
Use hasLinks([linkType]) method to get issue has atleast one link for more details see
https://www.j-tricks.com/jqlt-links-functions.html
Thanks,
Patina
Please see the plugin in atlassian marketplace. https://marketplace.atlassian.com/plugins/com.j-tricks.jql-plugin
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi Delphine,
If you have script runner plugin you can use
issuefunction in linkedissuesof('project=<YourProject>')
Cheers,
Udo
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Download version 1.2 from here
https://bitbucket.org/bhushan154/jira-miscellaneous-jql-functions/downloads#download-263929
And use the function
issue in issuesWithLinks(). Just added it haven't tested it yet. Let me know if you have any issues.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Here are the other functions
https://bitbucket.org/bhushan154/jira-miscellaneous-jql-functions/wiki/Home
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Online forums and learning are now in one easy-to-use experience.
By continuing, you accept the updated Community Terms of Use and acknowledge the Privacy Policy. Your public name, photo, and achievements may be publicly visible and available in search engines.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.