Get status and Resolution for a linked issue

[Brenda]

Hi, I really need your heeelp,

I need to change the status of an issue if following condition is true:

I have a linked Issue of type "Is Reviewed by"

linkedIssue status = close

and linkedIssue resolution = done

I know I have to use a fast track function to change the status but for the condition I have an error, What I'm doing:

issueLinkManager.getOutwardLinks(issue.getId())*.issueLinkType.name.contains('is reviewed by')

linkedIssues.getAsString("status") == ["Closed"]
linkedIssues.getAsString("resolution")==["Done"]

'linkedissues' is not recognized.

[Marc Minten (EVS) · Accepted solution]

Shouldn't you write

def linkedIssues = issueLinkManager.getOutwardLinks(...
linkedIssues.getAsString(...

?

[Brenda]

Hi Marc, thx!! I've tried:

def LinkedIssues = issueLinkManager.getOutwardLinks(issue.getId())*.issueLinkType.name.contains('Is Reviewed by')
LinkedIssues.getAsString('Status') = 'Closed'
LinkedIssues.getAsString('Resolution') ='Done'

But I had: "LinkedIssues.getAsString('Status')"  is a method call expression, but it should be a variable expression

:/

[Marc Minten (EVS)]

Sorry, I did not look in detaat

[Marc Minten (EVS)]

Sorry, I did not look in detail at your code.

You should loop over the linkedIssues, and test for each issue :

...
linkedIssue.getStatus().getName() == 'Closed'
linkedIssue.getResolution().getName() == 'Done'
...

[Brenda]

Thanks for you help Marc!!!