I'm using a JQL for a scrum board.
The JQL is:
(project = "<project name>" AND issuetype not in (Test, Sub-Task) AND status not in ("Needs CS Input", Triage) AND (component != RP or component is EMPTY)) or labels in (<LabelA>,<LabelB>) ORDER BY Rank ASC
Why does the label clause make this JQL too complicated for my Scrum Board? When I look at the Scrum Board's configuration, I see:
Projects in board: The projects in this board cannot be listed because of the complexity of the board filter
No matter which way I try to rewrite the JQL, the labels part makes it too complicated.
What am I missing?
Thank you!
That is because labels are a global object and could potentially return tickets from any project.
Are you trying to only return tickets from the project in the initial part of the query?
Thanks,
Kian
@Kian Stack Mumo Systems - Thank you for the quick response.
My actual issue that I'm running into is a scrum master lost the ability to close/start sprints. I've looked at their project and she has the Manage Sprints, Edit Sprints, and Start/Complete Sprints permissions. Knowing that she needs all of those permissions in all projects associated with the board (indirectly the sprint), I was using the board to try and find other projects that I need to look at. As I was typing this, I realized that I can just use the JQL itself and look for Labels in (LabelA, LabelB) and it will return what I need.
Thank you for the great response!
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Online forums and learning are now in one easy-to-use experience.
By continuing, you accept the updated Community Terms of Use and acknowledge the Privacy Policy. Your public name, photo, and achievements may be publicly visible and available in search engines.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.