Simple Script Validators - exact number of digits

[Anna Protopapa]

Hello,

I want to have a validation for an optional field that has exactly 8 digits.

My code is:

 // Import Regex

import java.util.regex.*;

// Construct The Pattern to Match on

Pattern pattern = Pattern.compile("([0-9]){8}");

// Check if the PhoneNumber Field is a match

cfValues['PhoneNumber'] == null || pattern.matcher(issue.getCustomFieldValue(customFieldManager.getCustomFieldObjectByName("PhoneNumber")).toString())  

The problem is that allows can insert more than 8 digits.

[Tarun Sapra · Accepted solution]

Try this

Pattern.compile("^([0-9]{8})$")

[Tarun Sapra]

Anna you were missing the dollar sign ($) in your snippet which means "don't add anything after me" as dollar sign means end of line.

[Anna Protopapa]

It works with Pattern.compile("^([0-9]{8})\$")

Thank you

[Anna Protopapa]

I want to ask another case: If I need the number of digits to be between 5 to 8 digits, how I will write the command?

[Tarun Sapra]

Just make it

Pattern.compile("^([0-9]{5,8})\$")

[Tarun Sapra]

If it works for you, please accept the answer. thanks.

[Anna Protopapa]

Thank you!!

[Stefani Kaimakliotou]

What if we want to add special characters like "-" to the above snippet? e.g 9956-56

[Tarun Sapra]

Hi @Stefani Kaimakliotou

Your requirement of "9956-56" can be implemented with the snippet

Pattern.compile("^([-0-9]{5,8})\$")

i.e. digits with "-" (dash) and total length of 5 to 8